Files
suanfa/c/ch3/lcs/lcs1.c
T
2026-06-14 23:48:44 +08:00

89 lines
2.7 KiB
C

#include <stdio.h>
#include <string.h>
#define MAX 100
int getLCS(char* text1, char* text2) {
int t1_len = strlen(text1);
int t2_len = strlen(text2);
int dp[MAX][MAX] = {0};
for (int i = 1; i <= t1_len; i++) {
for (int j = 1; j <= t2_len; j++) {
if (text1[i - 1] == text2[j - 1]) {
//找到一个 lcs 的元素,继续往前找
dp[i][j] = 1 + dp[i - 1][j - 1];
} else {//谁能让 lcs 最长,就取谁的值
dp[i][j] = (dp[i - 1][j] > dp[i][j - 1])?
dp[i - 1][j] : dp[i][j - 1];
}
}
}
return dp[t1_len][t2_len];
}
void getLCSTable(int dp[MAX][MAX], char* text1, char* text2, char b[MAX][MAX]) {
int t1_len = strlen(text1);
int t2_len = strlen(text2);
for (int i = 1; i <= t1_len; i++) {
for (int j = 1; j <= t2_len; j++) {
if (text1[i - 1] == text2[j - 1]) {
dp[i][j] = 1 + dp[i - 1][j - 1];
b[i][j] = 'X'; // LCS元素,使用 'X' 作为占位符
} else if (dp[i - 1][j] >= dp[i][j - 1]) {
dp[i][j] = dp[i - 1][j];
b[i][j] = '|'; // 取上面的值
} else {
dp[i][j] = dp[i][j - 1];
b[i][j] = '-'; // 取左边的值
}
}
}
}
void printLCSTable(char b[MAX][MAX], char* t1, char* t2, int l1, int l2) {
printf("\t");
for (int j = 0; j < l2; j++)
printf("%c\t", t2[j]);
printf("\n");
for (int i = 0; i <= l1; i++) {
printf("%c\t", (i == 0) ? ' ' : t1[i - 1]);
for (int j = 0; j <= l2; j++) {
if (i == 0 && j == 0) {
printf("\t");
} else {
printf("%c\t", b[i][j]);
}
}
printf("\n");
}
}
void printLCSString(char b[MAX][MAX], char* x, int i, int j) {
if (i == 0 || j == 0) return;
if (b[i][j] == 'X') {
printLCSString(b, x, i - 1, j - 1);
// 打印当前字符
printf("%c", x[i - 1]);
} else if (b[i][j] == '|') {
printLCSString(b, x, i - 1, j);
} else {
printLCSString(b, x, i, j - 1);
}
}
int main() {
char t1[] = "ABCB";
char t2[] = "BDCA";
printf("字符串: %s 和字符串: %s 的 LCS 长度为: %d\n", t1, t2, getLCS(t1, t2));
printf("--------------------------------\n");
int dp[MAX][MAX] = {0};
char b[MAX][MAX] = {0};
getLCSTable(dp, t1, t2, b);
printLCSTable(b, t1, t2, strlen(t1), strlen(t2));
printf("-------------------------------\n");
printf("LCS 字符串为: ");
printLCSString(b, t1, strlen(t1), strlen(t2));
printf("\n");
return 0;
}