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#include <stdio.h>
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int main() {
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int money[] = {100, 50, 20, 10, 5, 1};
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int n = 85;
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printf("要找的钱数为:%d\n", n);
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int num[6] = {0}; // 存储每种面值所需的数量
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for (int i = 0; i < 6; i++) {
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num[i] = n / money[i]; // 计算需要的面值数量
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n = n % money[i]; // 更新剩余的钱数
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}
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for (int i = 0; i < 6; i++) {
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printf("需要%d元面值%d枚\n", money[i], num[i]);
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}
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return 0;
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}
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